Grade 116 grade maths
Find a number who is divided by 9,11&13 gives remainder 1,2&3 respectively.
Find a number who is divided by 9,11&13 gives remainder 1,2&3 respectively.
4 Answers
Arun
let the no be x;
x=9a+1;
x=11b+2;
x=13c+3;
multiply all equations by 2:
2x=9d+2;
2x=11e+4;
2x=13f+6;
now add 7 to all;
2x+7=9d+9; divisible by 9
2x+7=11e+11; divisible by 11
2x+7=11e+11; divisible by 11
2x+7=13f+13; divisible by 13
therefore LCM(9,11,13)=2x+7
(9*11*13-7)/2=x
=>x=640, if not 640 then keep multiplying by 2,3,4,5,6,etc
we take LCM because it is the smallest no which has 9,11,13 as factor
TADA POOJAN
First number
9-1 = 8
Second number
11-2 = 9
Third number
13-3= 10
Therefore the LCM of 8,9,and10 is equal to 360
Ashish
It's qnswea is 640. 360 is divided by 9 gives remainder 0. 360 is divided by 11 then gives remainder 8
john cena
subtracting remaider means 8,9 and 10 should be divisible by any common number
by l.c.m of 8,9,10
the number comes 360
so the number which is divided by 8,9,10 is 360
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