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Find a number who is divided by 9,11&13 gives remainder 1,2&3 respectively.

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2 years ago

```							 let the no be x;x=9a+1;x=11b+2; x=13c+3;multiply all equations by 2:2x=9d+2;2x=11e+4;2x=13f+6;now add 7 to all;2x+7=9d+9;     divisible by 92x+7=11e+11;    divisible by 112x+7=13f+13;    divisible by 13therefore LCM(9,11,13)=2x+7(9*11*13-7)/2=x=>x=640, if not 640 then keep multiplying by 2,3,4,5,6,etcwe take LCM because it is the smallest no which has 9,11,13 as factor
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2 years ago
```							First number9-1 = 8Second number 11-2 = 9Third number 13-3= 10Therefore the LCM of 8,9,and10 is equal to 360
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2 years ago
```							It's qnswea is 640.  360 is divided by 9 gives remainder 0. 360 is divided by 11 then gives remainder 8
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2 years ago
```							subtracting remaider means 8,9 and 10 should be divisible by any common numberby l.c.m of 8,9,10the number comes 360 so the number which is divided by 8,9,10 is 360
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2 years ago
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