Consider the infinite sequence {n^1/n } i.e. 1 , 2

Question

Consider the infinite sequence {n^1/n } i.e. 1 , 2^1/2 , 3^1/3 . . . . .Find the largest term in this sequence(if it exists). hint : use calculas

Rinkoo Gupta · Accepted Answer

lim n->infinity n^1/nlet A=lim n->infinity n^1/ntaking log on both sideslog A=lim n->infinity (logn)/n form infinity/infinityUsing L'Hospital rulelogA=lim n->infinity (1/n)/1=>logA=limn->infinity(1/n)=>logA=1/infinity=0=>A=e^0=1Hence gthe largest Term in this sequence is 1.Thanks & RegardsRinkoo GuptaAskIITians Faculty

6 grade maths> Consider the infinite sequence {n^1/n } i...

Consider the infinite sequence {n^1/n } i.e. 1 , 2^1/2 , 3^1/3 . . . . .Find the largest term in this sequence(if it exists). hint : use calculas

sanjeev100 , 11 Years ago

Rinkoo Gupta

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6 grade maths> Consider the infinite sequence {n^1/n } i...

Consider the infinite sequence {n^1/n } i.e. 1 , 2^1/2 , 3^1/3 . . . . .Find the largest term in this sequence(if it exists). hint : use calculas

sanjeev100 , 11 Years ago

Rinkoo Gupta

LIVE ONLINE CLASSES

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