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A shell is fired from a gun and has a horizontal range of 960m and time of flight of 12s. Find the magnitude and direction of the velocity of projection. (take )
A shell is fired from a gun and has a horizontal range of 960m and time of flight of 12s. Find the magnitude and direction of the velocity of projection. (take )


3 years ago

Arun
25768 Points
							using distance = velocity * timefor horizontal motion960 = U* 12U = 80 m/sec using  s = ut + ½ a t2 for vertical motion0 = V* 12 – ½ *10* 122V = 60 m/sec speed of projection = $\sqrt$(u2 + v2) = $\sqrt$6400+3600 = $\sqrt$10000 = 100 m/sec. the angle of projection is $\theta$ above the horizontaltan$\theta$ = 60/80 = ¾$\theta$ = 36.87 hencethe shell is projected at 100 m/secat an angle of 36.87 degree above the horizontal.

3 years ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions