Arun
Last Activity: 7 Years ago
using distance = velocity * time
for horizontal motion
960 = U* 12
U = 80 m/sec
using s = ut + ½ a t2
for vertical motion
0 = V* 12 – ½ *10* 122
V = 60 m/sec
speed of projection =
(u
2 + v
2)
=
6400+3600 =
10000
= 100 m/sec.
the angle of projection is
above the horizontal
tan
= 60/80 = ¾
= 36.87
hencethe shell is projected at 100 m/secat an angle of 36.87 degree above the horizontal.
