Grade 66 grade maths
4ab5 is a four digit number divisible by 55 where a, b are unknown digits. Then b – a is :
4ab5 is a four digit number divisible by 55 where a, b are unknown digits. Then b – a is :
2 Answers
Sourabh Singh
Approved Tutor Answer9 Years agohii
It is very easy as he number given is a multiple of 11*5 so it must follow he divsibility rule of 11 and 5
use that and you will get the relation in a and b which will give you answer
It is very easy as he number given is a multiple of 11*5 so it must follow he divsibility rule of 11 and 5
use that and you will get the relation in a and b which will give you answer
Yuvraj Singh
55=5*11.
We know in the no. 4ab5 last digit is 5 so its divisible by 5.
Its divisible by 11 also if its divisible by 11 then the sum of its odd and even terms must be divisible by
11.
4+b-(a+5)=a no. Divisible by 11.
b-a=(a no. Divisible by 11 ) +1.
now since b and a are single digit no. so 0 is the only no. which satisfies the equation. So the answer is 1.
Other Related Questions on 6 grade maths
Fill in the blank:
____________ INR 100 notes make 500 rupees.
- A. 5
- B. 6
- C. 7
- D. 4
Fill in the blank:
____________ INR 100 notes make 500 rupees.
- A. 5
- B. 6
- C. 7
- D. 4
6 grade maths
Last Activity: 11 Months ago