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What is the angle made by a refracted ray with the normal inside a regular (equilateral) prism, in minimum deviation case?

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9 Months agoGrade
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ApprovedApproved Tutor Answer9 Months ago

The angle made by a refracted ray with the normal inside a regular (equilateral) prism during the minimum deviation case is a key concept in optics.

Understanding the Minimum Deviation

In the context of a prism, minimum deviation occurs when light passes through the prism at a specific angle, resulting in the least bending of the light ray. For an equilateral prism, where all angles are equal (60 degrees), this situation is particularly interesting.

Angle Calculation

When light enters and exits the prism at minimum deviation, the angle of refraction inside the prism can be determined using the following relationship:

  • The angle of the prism (A) is 60 degrees.
  • The angle of minimum deviation (D) can be calculated using Snell's law.

In this case, the angle made by the refracted ray with the normal inside the prism is:

r = (A + D) / 2

Since A is 60 degrees, and at minimum deviation, D is equal to the angle of incidence minus the angle of refraction, you can find the angle of refraction (r) to be:

r = (60 + D) / 2

Final Insight

Thus, in the minimum deviation case for an equilateral prism, the angle made by the refracted ray with the normal is half the sum of the prism angle and the angle of minimum deviation. This relationship is crucial for understanding how light behaves when passing through different media.