To derive the expression for the magnetic field at any point on the axial line of a current-carrying circular loop using Biot-Savart’s law, we start with the law itself, which states that the magnetic field \( \mathbf{B} \) due to a small segment of current \( I \, d\mathbf{l} \) at a point in space is given by:
Biot-Savart's Law
The formula is expressed as:
dB = \frac{\mu_0}{4\pi} \frac{I \, d\mathbf{l} \times \mathbf{r}}{r^3}
where \( \mu_0 \) is the permeability of free space, \( \mathbf{r} \) is the position vector from the current element to the point where the field is being calculated, and \( r \) is the distance from the current element to that point.
Setup for the Circular Loop
Consider a circular loop of radius \( R \) carrying a current \( I \). We want to find the magnetic field at a point along the axis of the loop, at a distance \( z \) from the center of the loop.
Calculating the Magnetic Field
- Each small segment \( d\mathbf{l} \) of the loop contributes to the magnetic field at the point on the axis.
- The distance from the segment to the point is \( r = \sqrt{R^2 + z^2} \).
- The angle \( \theta \) between \( d\mathbf{l} \) and \( \mathbf{r} \) is such that \( \sin \theta = \frac{R}{r} \) and \( \cos \theta = \frac{z}{r} \).
Using symmetry, the vertical components of the magnetic field from opposite segments cancel out, leaving only the axial components. Thus, the total magnetic field \( B \) at the point on the axis is:
B = \frac{\mu_0 I R^2}{2(R^2 + z^2)^{3/2}}
Magnitude at the Center of the Coil
To find the magnetic field intensity at the center of the circular coil, we set \( z = 0 \). Substituting this into our expression gives:
B_{center} = \frac{\mu_0 I}{2R}
This result shows that the magnetic field at the center of a circular coil is directly proportional to the current and inversely proportional to the radius of the coil.