The Vividh Bharati Station of All India Radio Delhi broadcasts on a frequency of 1,368 kHz. Calculate the wavelength ( λ) of the electromagnetic radiation emitted by the transmitter. Which part of the electromagnetic spectrum does it belong to?A. 319.4m and X- raysB. 319.4m and radio waveC. 219.3m and microwaveD. 219.3m and radio wave

To calculate the wavelength (λ) of the electromagnetic radiation emitted by the Vividh Bharati Station, we can use the formula:

λ = c / f

where λ represents the wavelength, c is the speed of light, and f is the frequency.

The given frequency is 1,368 kHz, which can be converted to 1.368 MHz (1 MHz = 1,000 kHz).

The speed of light, c, is approximately 3 x 10^8 meters per second.

Using the formula, we can calculate the wavelength:

λ = (3 x 10^8 m/s) / (1.368 x 10^6 Hz)
≈ 219.3 meters

Therefore, the wavelength (λ) of the electromagnetic radiation emitted by the Vividh Bharati Station is approximately 219.3 meters.

Based on the wavelength range, it belongs to the radio wave part of the electromagnetic spectrum. So, the correct answer is option D: 219.3m and radio wave.