The circuit has two oppositely connected ideal diodes in parallel. What is the current flowing in the circuit?

A) 1.71 A
B) 2.0 A
C) 2.31 A
D) 1.33 A

Let's solve this step by step.

Given: Two oppositely connected ideal diodes in parallel.

In a circuit with diodes connected in parallel but oppositely, one diode will conduct current when the polarity is forward biased, and the other diode will conduct current when the polarity is reversed.

Ideal Diodes:

In ideal diodes, when the diode is forward biased, it has zero voltage drop and conducts current without resistance.
When the diode is reverse biased, it does not conduct any current (acts as an open circuit).
Assumptions:

The circuit is a simple one where the voltage source is known, and there are two diodes.
Each diode is ideal, meaning no voltage drop across them when forward biased.
Analysis:

If the circuit has a DC voltage source and the diodes are oriented oppositely, one of the diodes will be forward biased and the other reverse biased.
The forward biased diode will conduct, and the reverse biased one will block the current.
Calculating Current:

If the voltage of the source is given, we can calculate the current flowing through the conducting diode using Ohm's Law: I = V/R, where V is the voltage and R is the resistance in the circuit.
Since the diodes are ideal, the current only depends on the voltage and resistance.
Since the options provided (1.71 A, 2.0 A, 2.31 A, 1.33 A) suggest a specific current value, we need the voltage or resistance values to calculate the exact current. Without additional information about the voltage or resistance, we cannot solve the exact current.

However, based on the given answer choices, if we assume the problem is asking for the total current after one diode conducts, the current could be 2.0 A, assuming a common circuit configuration and typical voltage value.

Answer: B) 2.0 A