To analyze how the reversal of the Ge diode affects \( V_o \), let's first understand the circuit configuration. I'll assume the circuit consists of a series arrangement of a Ge diode and a Si diode, with \( V_o \) being the output voltage across these diodes.
### Original Configuration
In the original configuration, let’s assume:
- The Ge diode (with a forward voltage of 0.3 V) is connected with its anode to the positive side of the voltage source and its cathode to the anode of the Si diode.
- The Si diode (with a forward voltage of 0.7 V) is connected with its cathode to the output \( V_o \).
So, the total forward voltage drop in the circuit is:
\[ V_{\text{drop}} = V_{\text{Ge}} + V_{\text{Si}} = 0.3\, \text{V} + 0.7\, \text{V} = 1.0\, \text{V} \]
Thus, \( V_o \) is equal to the source voltage minus 1.0 V.
### Reversed Ge Diode Configuration
If the Ge diode is reversed:
- The anode of the Ge diode will now be connected to the cathode of the Si diode and its cathode to the voltage source.
In this reversed configuration, the Ge diode will not conduct if its reverse breakdown voltage is high, and the Si diode will conduct as before. Therefore, the voltage drop across the Si diode remains 0.7 V, but now the Ge diode will not contribute to the forward voltage drop, leading to a change in the output voltage.
The value of \( V_o \) in this case will be the source voltage minus only the voltage drop of the Si diode:
\[ V_o' = V_{\text{source}} - V_{\text{Si}} = V_{\text{source}} - 0.7\, \text{V} \]
### Change in Output Voltage
The change in output voltage \( \Delta V_o \) is given by:
\[ \Delta V_o = (V_{\text{source}} - 0.7\, \text{V}) - (V_{\text{source}} - 1.0\, \text{V}) = 1.0\, \text{V} - 0.7\, \text{V} = 0.3\, \text{V} \]
So, the output voltage \( V_o \) changes by \( 0.3\, \text{V} \) when the Ge diode is reversed.
Since none of the options directly match this calculation, there might be an error or additional context in the problem setup that would affect the provided choices. However, based on the standard interpretation, the correct change should be \( 0.3\, \text{V} \).
