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Force due to electrostatic pressure is directed outwards normal to the surface. Force on a small element ds of a charged conductor dF = (charge on ds) times Electric field = (σ ds) σ / (2ε₀) = σ² / (2ε₀) ds. Inside E₁ - E₂ = 0 ⇒ E₁ = E₂. Just outside E = E₁ + E₂ = 2E₂ ⇒ E₂ = σ / (2ε₀). (E₁ is the field due to charge on the element ds of the surface and E₂ is the field due to the rest of the sphere). The electric force acting per unit area of charged surface is defined alone.

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11 Months agoGrade
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ApprovedApproved Tutor Answer11 Months ago

Let's break down the concept of electrostatic pressure and the forces acting on a charged conductor. This topic is fundamental in electrostatics and helps us understand how electric fields interact with charged surfaces. We'll explore how the electric field behaves at the surface of a charged conductor and derive the expression for the electrostatic pressure.

Understanding Electrostatic Pressure

When we have a charged conductor, the charges redistribute themselves on the surface. This redistribution creates an electric field both inside and outside the conductor. The key point is that the electric field inside a perfect conductor in electrostatic equilibrium is zero. This means that any electric field lines must terminate on the surface of the conductor.

Force on a Small Element

Consider a small surface element, denoted as ds, on the charged conductor. The charge on this element can be expressed as:

  • Charge on ds: σ ds

Here, σ represents the surface charge density (charge per unit area). The force acting on this small element due to the electric field can be calculated using the formula:

  • Force (dF): dF = (charge on ds) × (Electric field)
  • Substituting, we get: dF = (σ ds) × (E)

For a charged conductor, the electric field just outside the surface can be derived from Gauss's law. The electric field just outside the surface of a charged conductor is given by:

  • Electric Field (E): E = σ / (2ε₀)

Thus, the force acting on the small element ds becomes:

  • dF: dF = (σ ds) × (σ / (2ε₀)) = σ² / (2ε₀) ds

Electric Field Inside and Outside the Conductor

Now, let's analyze the electric fields inside and outside the conductor. Inside the conductor, we have:

  • Electric Field (E₁): E₁ = 0
  • Electric Field (E₂): E₂ = σ / (2ε₀)

According to the principles of electrostatics, the electric field just outside the surface of the conductor (E) can be expressed as:

  • Just Outside Electric Field: E = E₁ + E₂ = 2E₂

From this, we can conclude that:

  • Electric Field Just Outside (E): E = σ / ε₀
  • Thus, E₂: E₂ = σ / (2ε₀)

Electrostatic Pressure on the Charged Surface

The electric force acting per unit area on the charged surface is what we define as electrostatic pressure. This pressure can be derived from the force per unit area acting on the surface:

  • Electrostatic Pressure (P): P = dF / ds = (σ² / (2ε₀))

This equation tells us that the electrostatic pressure on the surface of a charged conductor is directly proportional to the square of the surface charge density and inversely proportional to the permittivity of free space (ε₀).

Summary of Key Points

To summarize, the electrostatic pressure on a charged conductor arises from the forces acting on small surface elements due to the electric field created by the surface charges. The electric field just outside the conductor is crucial for determining this pressure, and it is derived from the surface charge density. Understanding these principles is essential for applications in electrostatics, such as in capacitors and other electrical devices.