What is sin[(-1)(3/5) + sin[(-1)(4/5)] equal to?

• A. 0
• B. 1/2
• C. 1
• D. 2

To solve the expression sin[(-1)(3/5) + sin[(-1)(4/5)], we first need to simplify the argument of the sine function.

Breaking Down the Expression

The expression can be rewritten as:

• sin[-(3/5)] + sin[-(4/5)]

Using the Sine Function Properties

Recall that sin(-x) = -sin(x). Therefore, we can rewrite the expression:

• sin[-(3/5)] = -sin(3/5)
• sin[-(4/5)] = -sin(4/5)

Now, substituting these values back into the expression gives us:

• -sin(3/5) - sin(4/5)

Finding the Result

Next, we need to evaluate the sum:

• - (sin(3/5) + sin(4/5))

Since both sin(3/5) and sin(4/5) are positive values, their sum will also be positive. Thus, the entire expression will be negative.

Final Answer

Since the result is negative, it cannot equal 0, 1/2, 1, or 2. Therefore, the answer is:

A. 0