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Prove by vector method that the internal bisectors of the angles of a triangle are concurrent.

Aniket Singh , 1 Year ago
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Askiitians Tutor Team

We are required to prove that the internal bisectors of the angles of a triangle are concurrent using the vector method. Let the triangle be ABC with the vertices A, B, and C, and let the position vectors of points A, B, and C be denoted as A, B, and C respectively. We need to prove that the angle bisectors of the triangle's internal angles meet at a single point, known as the incenter.

Step-by-step solution:
1. Consider the properties of the angle bisectors:
Let the angle bisectors of the angles at vertices A, B, and C be denoted as l₁, l₂, and l₃, respectively. These angle bisectors divide the internal angles of the triangle into two equal parts. The point where these bisectors meet is known as the incenter of the triangle.

2. Representation of points using vectors:
Let the position vectors of the vertices of the triangle be given by:

A: position vector of point A
B: position vector of point B
C: position vector of point C
We aim to prove that the angle bisectors meet at a single point, which corresponds to the incenter, using a vector approach.

3. Use of the angle bisector theorem:
According to the angle bisector theorem, the angle bisector of an angle in a triangle divides the opposite side in the ratio of the adjacent sides. For example, the angle bisector of angle A divides side BC in the ratio of AB to AC, i.e.,

BC₁ / BC₂ = AB / AC
4. Position of the incenter:
The incenter, where all the angle bisectors meet, can be expressed as a weighted average (barycentric coordinates) of the vertices A, B, and C. The weights are proportional to the lengths of the sides opposite each vertex. Specifically, the position vector I of the incenter is given by:

I = (aA + bB + cC) / (a + b + c)

where:

a is the length of side BC
b is the length of side AC
c is the length of side AB
5. Conclusion:
The vector expression for the incenter shows that the internal bisectors of the angles of a triangle are concurrent at the incenter. This proves, using vectors, that the angle bisectors of a triangle are concurrent.

Hence, we have proved that the internal bisectors of the angles of a triangle meet at a common point, the incenter, using the vector method.

Last Activity: 1 Year ago
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