Flag 12 grade maths others> Integrate the functions ex x2</...
question mark

Integrate the functions ex x2.

Aniket Singh , 6 Months ago
Grade
anser 1 Answers
Askiitians Tutor Team

To integrate the function \( e^{x} \cdot x^{2} \), we can use the technique of integration by parts. This method is useful when dealing with the product of two functions.

Integration by Parts Formula

The formula for integration by parts is:

∫ u dv = uv - ∫ v du

Here, we need to choose \( u \) and \( dv \) from our function \( e^{x} \cdot x^{2} \).

Choosing u and dv

  • Let: \( u = x^{2} \) (which simplifies when differentiated)
  • Then: \( du = 2x \, dx \)
  • Let: \( dv = e^{x} \, dx \)
  • Then: \( v = e^{x} \)

Applying the Formula

Now, we can apply the integration by parts formula:

∫ \( e^{x} \cdot x^{2} \, dx = x^{2} \cdot e^{x} - ∫ e^{x} \cdot 2x \, dx \)

Integrating the Remaining Integral

Next, we need to integrate \( ∫ e^{x} \cdot 2x \, dx \) using integration by parts again:

  • Let: \( u = 2x \)
  • Then: \( du = 2 \, dx \)
  • Let: \( dv = e^{x} \, dx \)
  • Then: \( v = e^{x} \)

Applying the formula again gives:

∫ \( e^{x} \cdot 2x \, dx = 2x \cdot e^{x} - ∫ 2e^{x} \, dx \)

Final Steps

The integral of \( 2e^{x} \) is simply \( 2e^{x} \). So we have:

∫ \( e^{x} \cdot 2x \, dx = 2x \cdot e^{x} - 2e^{x} \)

Putting It All Together

Now, substituting back into our original integration:

∫ \( e^{x} \cdot x^{2} \, dx = x^{2} \cdot e^{x} - (2x \cdot e^{x} - 2e^{x}) + C \)

Thus, the final result is:

∫ e^{x} \cdot x^{2} \, dx = e^{x}(x^{2} - 2x + 2) + C

ApprovedApproved
Last Activity: 6 Months ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments