To solve the problem of how to invest Rs. 30,000 in two types of bonds using matrix multiplication, we can set up a system of equations based on the interest rates and the total interest required.
Setting Up the Problem
Let:
- x = amount invested in the first bond (5% interest)
- y = amount invested in the second bond (7% interest)
The total investment can be expressed as:
x + y = 30000
Interest Equations
The total interest from both bonds can be represented as:
- For Rs. 1800 interest: 0.05x + 0.07y = 1800
- For Rs. 2000 interest: 0.05x + 0.07y = 2000
Matrix Representation
We can represent the system of equations in matrix form:
For Rs. 1800:
Matrix A:
And the corresponding matrix for the constants:
Matrix B:
Solving the System
Using matrix methods, we can solve for x and y:
For Rs. 1800:
1. From the first equation, y = 30000 - x
2. Substitute into the second equation:
0.05x + 0.07(30000 - x) = 1800
3. Simplifying gives:
0.05x + 2100 - 0.07x = 1800
-0.02x = -300
x = 15000
4. Thus, y = 30000 - 15000 = 15000
For Rs. 2000, repeat the process:
1. Substitute into the second equation:
0.05x + 0.07(30000 - x) = 2000
2. Simplifying gives:
0.05x + 2100 - 0.07x = 2000
-0.02x = -100
x = 5000
3. Thus, y = 30000 - 5000 = 25000
Final Investment Distribution
To achieve the desired interest:
- For Rs. 1800: Invest Rs. 15,000 in the first bond and Rs. 15,000 in the second bond.
- For Rs. 2000: Invest Rs. 5,000 in the first bond and Rs. 25,000 in the second bond.