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A pair of dice is thrown 4 times. If getting a doublet is considered a success, find the probability distribution of number of successes.

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9 Months agoGrade
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ApprovedApproved Tutor Answer9 Months ago

To find the probability distribution of the number of successes when throwing a pair of dice four times, we first need to determine the probability of getting a doublet (two dice showing the same number) in a single throw.

Calculating the Probability of a Doublet

When rolling two dice, there are a total of 6 possible doublets: (1,1), (2,2), (3,3), (4,4), (5,5), and (6,6). Since there are 36 possible outcomes when rolling two dice (6 sides on the first die multiplied by 6 sides on the second die), the probability of rolling a doublet is:

  • P(Doublet) = Number of Doublets / Total Outcomes
  • P(Doublet) = 6 / 36 = 1/6

Defining the Random Variable

Let X be the random variable representing the number of successes (doublets) in 4 throws. Since each throw is independent, X follows a binomial distribution:

  • n = 4 (number of trials)
  • p = 1/6 (probability of success)

Probability Distribution Function

The probability mass function for a binomial distribution is given by:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where C(n, k) is the binomial coefficient, calculated as:

C(n, k) = n! / (k!(n-k)!)

Calculating Probabilities for Each Outcome

Now, we can calculate the probabilities for k = 0, 1, 2, 3, and 4 successes:

  • P(X = 0) = C(4, 0) * (1/6)^0 * (5/6)^4 = 1 * 1 * (625/1296) = 625/1296
  • P(X = 1) = C(4, 1) * (1/6)^1 * (5/6)^3 = 4 * (1/6) * (125/216) = 500/1296
  • P(X = 2) = C(4, 2) * (1/6)^2 * (5/6)^2 = 6 * (1/36) * (25/36) = 150/1296
  • P(X = 3) = C(4, 3) * (1/6)^3 * (5/6)^1 = 4 * (1/216) * (5/6) = 20/1296
  • P(X = 4) = C(4, 4) * (1/6)^4 * (5/6)^0 = 1 * (1/1296) * 1 = 1/1296

Summary of the Probability Distribution

The probability distribution of the number of successes (doublets) when throwing a pair of dice four times is:

  • P(X = 0) = 625/1296
  • P(X = 1) = 500/1296
  • P(X = 2) = 150/1296
  • P(X = 3) = 20/1296
  • P(X = 4) = 1/1296

This distribution provides a clear view of the likelihood of achieving different numbers of doublets in four rolls of a pair of dice.