Askiitians Tutor Team
Last Activity: 5 Months ago
To determine the probabilities of the events when a coin is tossed three times, we first need to understand the total number of possible outcomes. Each toss of a coin has two possible results: heads (H) or tails (T). When tossing the coin three times, the total number of outcomes can be calculated using the formula for combinations of independent events.
Total Outcomes
For three tosses, the total number of outcomes is calculated as follows:
- Each toss has 2 outcomes (H or T).
- For three tosses: 2 × 2 × 2 = 23 = 8.
Thus, the possible outcomes are: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT.
Event A: Getting at least two heads
To find the probability of getting at least two heads, we need to identify the outcomes that meet this criterion. The outcomes with at least two heads are:
Counting these, we find there are 4 favorable outcomes. Therefore, the probability of event A is:
P(A) = Number of favorable outcomes / Total outcomes = 4 / 8 = 1/2.
Event B: Getting exactly two heads
Next, we look for the outcomes that result in exactly two heads. The favorable outcomes for this event are:
There are 3 outcomes that satisfy this condition. Thus, the probability of event B is:
P(B) = Number of favorable outcomes / Total outcomes = 3 / 8.
Event C: Getting at most one head
For event C, we need to find the outcomes that have at most one head. The outcomes that fit this description are:
Counting these, we see there are 4 outcomes. Therefore, the probability of event C is:
P(C) = Number of favorable outcomes / Total outcomes = 4 / 8 = 1/2.
Summary of Probabilities
To summarize, the probabilities for the events are as follows:
- P(A) = 1/2 (at least two heads)
- P(B) = 3/8 (exactly two heads)
- P(C) = 1/2 (at most one head)
Understanding these probabilities helps in grasping the fundamental concepts of probability theory, especially in scenarios involving independent events like coin tosses.