Question icon
12 grade chemistry others

What happens when acetaldehyde is treated with phenylhydrazine? Give a balanced chemical equation?

Profile image of Aniket Singh
1 Year agoGrade
Answers icon

1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

When acetaldehyde is treated with phenylhydrazine, a condensation reaction occurs, resulting in the formation of a hydrazone. This reaction is significant in organic chemistry, particularly in the context of identifying carbonyl compounds. Let’s break down the process and the balanced chemical equation involved.

The Reaction Process

Acetaldehyde (CH₃CHO) is an aldehyde, which means it has a carbonyl group (C=O) at the end of its carbon chain. Phenylhydrazine (C₆H₅NH-NH₂) is a hydrazine derivative that reacts with carbonyl compounds. The reaction involves the nucleophilic attack of the hydrazine on the carbonyl carbon of acetaldehyde, leading to the formation of a hydrazone.

Step-by-Step Mechanism

  • Nucleophilic Attack: The nitrogen atom in phenylhydrazine, which has a lone pair of electrons, attacks the electrophilic carbon of the carbonyl group in acetaldehyde.
  • Proton Transfer: A proton transfer occurs, stabilizing the intermediate formed during the reaction.
  • Water Elimination: The reaction proceeds with the elimination of a water molecule, resulting in the formation of the hydrazone.

The Balanced Chemical Equation

The overall reaction can be represented by the following balanced chemical equation:

CH₃CHO + C₆H₅NH-NH₂ → C₆H₅N=CH-CO-CH₃ + H₂O

Understanding the Products

The product, known as phenylhydrazone, features a double bond between the nitrogen and the carbon that was originally part of the carbonyl group. This compound can be useful for further chemical analysis and identification of aldehydes and ketones due to its distinct properties.

Applications and Importance

This reaction is not only a fundamental transformation in organic synthesis but also serves practical purposes in laboratory settings. For instance, the formation of hydrazones can help in the characterization of aldehydes and ketones through techniques like melting point determination and spectroscopic analysis.

In summary, the reaction of acetaldehyde with phenylhydrazine leads to the formation of a hydrazone, showcasing the reactivity of carbonyl compounds and the utility of hydrazine derivatives in organic chemistry.


question mark

is Pradeep Chemistry+Ncert sufficient for all of the theory of Jee Mains Chemistry?


Hi, I’m a self-study JEE 2027 aspirant with a large 11th backlog. Since I don’t think 6–8 hour one-shots are sufficient to cover the full theory + breadth of problem types of a JEE chapter, I’ve shifted from lecture-based preparation to book-based self-study.


I have a problem with using NCERT as my primary chemistry source. In my experience, it is concise and information-heavy, but often lacks detailed explanations, systematic organisation of concepts, and categorisation of problem types. This seems especially problematic for Physical and Organic Chemistry, where I feel that simply reading NCERT may not give enough depth or problem-solving preparation.


So I’m considering this approach:


Pradeep Chemistry → complete the chapter thoroughly from Pradeep → then read NCERT for that chapter → solve JEE Main PYQs/problems.


My main question is:


Is Pradeep + NCERT sufficient as the complete theory source for JEE Main-level Chemistry?


In other words, after thoroughly completing a chapter from Pradeep and then NCERT, can I consider the theory part of that chapter complete for JEE Main, with only PYQs/problem practice remaining?


I’m asking specifically about JEE Main level, not Advanced.


Also, if Pradeep is not sufficient, what specific gap does it leave, and what would you recommend as a better book-based alternative for self-study?

Grade 1212 grade chemistry others
0 Answer Available

Last Activity: 3 Days ago