The product obtained when nitrobenzene is reduced using Zn/NaOH is:A. azobenzeneB. AnilineC. hydrazobenzeneD. azoxybenzene

To determine the product formed when nitrobenzene is reduced using zinc (Zn) in the presence of sodium hydroxide (NaOH), let's break down the reaction step-by-step.

### Reaction Overview

1. **Nitrobenzene** \((C_6H_5NO_2)\) is a compound containing a nitro group \((-NO_2)\) attached to a benzene ring.
2. **Reduction Reaction**: In this reaction, the nitro group \((-NO_2)\) is reduced to an amine group \((-NH_2)\).

### Mechanism

- **Reduction Process**:
- When nitrobenzene is treated with zinc in an alkaline medium (NaOH), the nitro group is reduced through a series of steps:
1. Nitro group \((-NO_2)\) is converted to an intermediate product, which can be a nitroso compound \((-NO)\).
2. Further reduction leads to the formation of **aniline** \((C_6H_5NH_2)\).

### Final Product

The main product of the reduction of nitrobenzene using Zn/NaOH is **aniline**.

### Conclusion

Thus, the correct answer to the question is:

**B. Aniline**

### Summary

- **Nitrobenzene** \( \xrightarrow{Zn/NaOH} \) **Aniline**
- The reduction process involves converting the nitro group to an amino group, resulting in the formation of aniline as the final product.