To determine the equivalent mass of sodium thiosulphate (Na2S2O3·5H2O) in the given reaction, we first need to understand the concept of equivalent mass and how it relates to the stoichiometry of the reaction.
Understanding Equivalent Mass
The equivalent mass of a substance is defined as the mass of that substance that will combine with or displace one mole of hydrogen atoms (or 8 grams of oxygen, or 35.5 grams of chlorine, etc.). In redox reactions, the equivalent mass can also be calculated based on the number of electrons transferred in the reaction.
Analyzing the Reaction
In the reaction provided:
- 2Na2S2O3 + I2 → 2NaI + Na2S4O6
We see that sodium thiosulphate (Na2S2O3) is acting as a reducing agent. Each mole of Na2S2O3 can donate electrons to iodine (I2), which is being reduced to iodide (NaI).
Calculating Molar Mass
First, let's calculate the molar mass of sodium thiosulphate pentahydrate (Na2S2O3·5H2O):
- Na: 22.99 g/mol × 2 = 45.98 g/mol
- S: 32.07 g/mol × 2 = 64.14 g/mol
- O: 16.00 g/mol × 3 = 48.00 g/mol
- H2O: (2 × 1.01) + 16.00 = 18.02 g/mol × 5 = 90.10 g/mol
Now, summing these values gives:
Molar mass of Na2S2O3·5H2O = 45.98 + 64.14 + 48.00 + 90.10 = 248.22 g/mol
Determining the Number of Equivalents
In this reaction, each mole of Na2S2O3 can donate 2 electrons (since it reduces I2 to NaI). Therefore, the number of equivalents of Na2S2O3 is equal to the number of moles multiplied by the number of electrons transferred:
Number of equivalents = moles × n
Here, n = 2 (the number of electrons transferred per mole of Na2S2O3).
Calculating Equivalent Mass
The equivalent mass can be calculated using the formula:
Equivalent mass = Molar mass / n
Substituting the values we have:
Equivalent mass = 248.22 g/mol / 2 = 124.11 g/equiv
Final Answer
Thus, the equivalent mass of sodium thiosulphate (Na2S2O3·5H2O) in the reaction is approximately 124 g/equiv. Therefore, the correct answer is B) 124.