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12 grade chemistry others

Standard electrode potential for Sn⁴⁺ | Sn²⁺ couple is + 0.15V and that for the Cr³⁺ | Cr couple is - 0.74V. These two couples in their standard state are connected to make a cell potential will be :

  • A. + 1.19V
  • B. + 0.89V
  • C. + 0.18V
  • D. + 1.83V

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1 Year agoGrade
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1 Answer

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Askiitians Tutor Team

ApprovedApproved Tutor Answer1 Year ago

To determine the cell potential when connecting the Sn⁴⁺ | Sn²⁺ couple with the Cr³⁺ | Cr couple, we need to apply the concept of standard electrode potentials. The cell potential (E_cell) can be calculated using the formula:

Understanding Standard Electrode Potentials

Standard electrode potential is a measure of the tendency of a chemical species to be reduced, measured in volts (V). A positive value indicates a greater tendency to gain electrons (be reduced), while a negative value indicates a lesser tendency.

Identifying the Half-Reactions

We have two half-reactions based on the given standard electrode potentials:

  • For the Sn⁴⁺ | Sn²⁺ couple:
    • Reduction: Sn⁴⁺ + 2e⁻ → Sn²⁺, E° = +0.15 V
  • For the Cr³⁺ | Cr couple:
    • Reduction: Cr³⁺ + 3e⁻ → Cr, E° = -0.74 V

Determining the Overall Cell Reaction

In a galvanic cell, the half-reaction with the higher standard electrode potential will occur as a reduction, while the one with the lower potential will occur as an oxidation. Therefore:

  • Oxidation (Cr): Cr → Cr³⁺ + 3e⁻, E° = +0.74 V (reverse the sign)
  • Reduction (Sn): Sn⁴⁺ + 2e⁻ → Sn²⁺, E° = +0.15 V

Balancing the Electrons

Before we can add these half-reactions, we need to ensure that the number of electrons lost in oxidation equals the number gained in reduction. The least common multiple of 2 and 3 is 6, so we multiply the half-reactions accordingly:

  • Oxidation: 2Cr → 2Cr³⁺ + 6e⁻
  • Reduction: 3Sn⁴⁺ + 6e⁻ → 3Sn²⁺

Calculating the Cell Potential

Now, we can find the overall cell potential by adding the standard electrode potentials of the two half-reactions:

E_cell = E°(reduction) + E°(oxidation)

E_cell = (+0.15 V) + (+0.74 V) = +0.89 V

Final Answer

Thus, the cell potential when connecting the Sn⁴⁺ | Sn²⁺ couple with the Cr³⁺ | Cr couple is +0.89 V. The correct answer is B. +0.89V.


question mark

is Pradeep Chemistry+Ncert sufficient for all of the theory of Jee Mains Chemistry?


Hi, I’m a self-study JEE 2027 aspirant with a large 11th backlog. Since I don’t think 6–8 hour one-shots are sufficient to cover the full theory + breadth of problem types of a JEE chapter, I’ve shifted from lecture-based preparation to book-based self-study.


I have a problem with using NCERT as my primary chemistry source. In my experience, it is concise and information-heavy, but often lacks detailed explanations, systematic organisation of concepts, and categorisation of problem types. This seems especially problematic for Physical and Organic Chemistry, where I feel that simply reading NCERT may not give enough depth or problem-solving preparation.


So I’m considering this approach:


Pradeep Chemistry → complete the chapter thoroughly from Pradeep → then read NCERT for that chapter → solve JEE Main PYQs/problems.


My main question is:


Is Pradeep + NCERT sufficient as the complete theory source for JEE Main-level Chemistry?


In other words, after thoroughly completing a chapter from Pradeep and then NCERT, can I consider the theory part of that chapter complete for JEE Main, with only PYQs/problem practice remaining?


I’m asking specifically about JEE Main level, not Advanced.


Also, if Pradeep is not sufficient, what specific gap does it leave, and what would you recommend as a better book-based alternative for self-study?

Grade 1212 grade chemistry others

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