Oxidation numbers of chlorine atoms in CaOC{l_2} areA. 0,0B. -1, -1C. -1, +1D. none of these

The oxidation number of an element indicates the charge that it would have in a compound or ion if electrons were completely transferred. To determine the oxidation numbers of the chlorine atoms in CaOCl2, we need to consider the oxidation numbers of calcium (Ca) and oxygen (O) first.

In CaO, calcium is in Group 2 of the periodic table and typically has a +2 oxidation number. Oxygen, which is highly electronegative, typically has an oxidation number of -2 in compounds.

Let's assign the oxidation number of chlorine as x.

For the compound CaOCl2, we can write the following equation based on the sum of oxidation numbers:

(2 x (+1)) + (-2) + 2(x) = 0

Simplifying the equation:

2 + (-2) + 2x = 0

0 + 2x = 0

2x = 0

x = 0

Therefore, the oxidation number of chlorine in CaOCl2 is 0.

Option A. 0,0 is the correct answer.