To solve this question, we need to understand the reaction involving N-ethyl phthalimide.
**N-Ethyl phthalimide** is a chemical compound where the ethyl group is attached to the nitrogen of the phthalimide structure.
When **N-ethyl phthalimide** undergoes hydrolysis, it reacts with water, usually in the presence of an acid or a base, to yield different products. The process is often carried out via a reaction known as the **phthalimide synthesis**.
Here’s a step-by-step explanation of the hydrolysis process:
1. **Hydrolysis of N-Ethyl Phthalimide:**
N-Ethyl phthalimide can be hydrolyzed under acidic or basic conditions to yield **ethylamine** and **phthalic acid**.
The general reaction is:
\[ \text{N-ethyl phthalimide} + \text{H}_2\text{O} \rightarrow \text{ethylamine} + \text{phthalic acid} \]
2. **Phthalic Acid Formation:**
During hydrolysis, the phthalimide ring breaks, and the product is phthalic acid. This occurs due to the acidic or basic hydrolysis conditions.
3. **Ethylamine Formation:**
The N-ethyl group on the phthalimide is converted into ethylamine during this hydrolysis.
**Conclusion:**
Upon hydrolysis, N-ethyl phthalimide yields **ethylamine** and phthalic acid. Thus, the correct answer is:
**B. Ethyl amine**