To solve this problem, let's first understand the working of a Daniell cell:
A Daniell cell is an electrochemical cell composed of a zinc electrode in a zinc sulfate (\( \text{ZnSO}_4 \)) solution and a copper electrode in a copper sulfate (\( \text{CuSO}_4 \)) solution. The zinc electrode acts as the anode, and the copper electrode acts as the cathode.
### Key Points about the Daniell Cell:
1. **Anode (Negative Electrode)**: The zinc electrode undergoes oxidation, losing electrons. The reaction is:
\[
\text{Zn} (s) \rightarrow \text{Zn}^{2+} (aq) + 2e^-
\]
Zinc loses electrons, so it is the anode (oxidation occurs here).
2. **Cathode (Positive Electrode)**: The copper electrode undergoes reduction, gaining electrons. The reaction is:
\[
\text{Cu}^{2+} (aq) + 2e^- \rightarrow \text{Cu} (s)
\]
Copper ions gain electrons, so it is the cathode (reduction occurs here).
### Flow of Electrons and Current:
- Electrons flow from the anode (zinc) to the cathode (copper) inside the cell.
- In the external circuit, conventional current (flow of positive charge) flows from the cathode (positive electrode) to the anode (negative electrode).
### Conclusion:
The statement says, "In a Daniel cell, current flows from cathode to anode outside the cell." This statement is true because the current flows from the positive terminal (cathode) to the negative terminal (anode) outside the cell.
**Answer: 1 (True)**