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12 grade chemistry others

How can I explain the monochlorination of alkanes?

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1 Year agoGrade
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Askiitians Tutor Team

ApprovedApproved Tutor Answer1 Year ago

The monochlorination of alkanes is a chemical reaction where one hydrogen atom in an alkane is replaced by a chlorine atom. This process is a type of substitution reaction and can be explained through several key steps.

What is Monochlorination?

Monochlorination specifically refers to the replacement of a single hydrogen atom with a chlorine atom in an alkane molecule. This reaction typically occurs in the presence of chlorine gas (Cl2) and requires energy, often provided by heat or ultraviolet light.

Steps Involved in Monochlorination

  • Initiation: The reaction begins when chlorine molecules are exposed to heat or light, causing them to break apart into two chlorine radicals (Cl·).
  • Propagation: A chlorine radical reacts with an alkane, removing a hydrogen atom and forming a new alkyl radical. This alkyl radical can then react with another chlorine molecule, resulting in the formation of monochlorinated alkane and another chlorine radical.
  • Termination: The reaction concludes when two radicals combine to form a stable molecule, stopping the chain reaction.

Example of Monochlorination

For instance, if we take methane (CH4) and react it with chlorine, the reaction can be summarized as follows:

  • CH4 + Cl2 → CH3Cl + HCl

In this example, one hydrogen atom from methane is replaced by a chlorine atom, resulting in chloromethane (CH3Cl) and hydrochloric acid (HCl).

Key Points to Remember

  • Monochlorination is a substitution reaction.
  • It involves radicals and can lead to multiple products if not controlled.
  • Understanding the mechanism helps predict the products formed in reactions with different alkanes.

In summary, monochlorination is a fascinating process that illustrates how alkanes can be transformed through the introduction of chlorine, showcasing the principles of organic chemistry in action.


question mark

is Pradeep Chemistry+Ncert sufficient for all of the theory of Jee Mains Chemistry?


Hi, I’m a self-study JEE 2027 aspirant with a large 11th backlog. Since I don’t think 6–8 hour one-shots are sufficient to cover the full theory + breadth of problem types of a JEE chapter, I’ve shifted from lecture-based preparation to book-based self-study.


I have a problem with using NCERT as my primary chemistry source. In my experience, it is concise and information-heavy, but often lacks detailed explanations, systematic organisation of concepts, and categorisation of problem types. This seems especially problematic for Physical and Organic Chemistry, where I feel that simply reading NCERT may not give enough depth or problem-solving preparation.


So I’m considering this approach:


Pradeep Chemistry → complete the chapter thoroughly from Pradeep → then read NCERT for that chapter → solve JEE Main PYQs/problems.


My main question is:


Is Pradeep + NCERT sufficient as the complete theory source for JEE Main-level Chemistry?


In other words, after thoroughly completing a chapter from Pradeep and then NCERT, can I consider the theory part of that chapter complete for JEE Main, with only PYQs/problem practice remaining?


I’m asking specifically about JEE Main level, not Advanced.


Also, if Pradeep is not sufficient, what specific gap does it leave, and what would you recommend as a better book-based alternative for self-study?

Grade 1212 grade chemistry others

Last Activity: 10 Days ago