[email protected]
India's First Online IIT-JEE & NEET Coaching Platform - Trusted Since 2006
+91-87964 74404
Question icon
12 grade chemistry others

Give one chemical test to distinguish between aniline and benzylamine.

Profile image of Aniket Singh
1 Year agoGrade
Answers icon

1 Answer

Profile image of Askiitians Tutor Team

Askiitians Tutor Team

ApprovedApproved Tutor Answer1 Year ago

To differentiate between aniline and benzylamine, one effective chemical test involves the use of nitrous acid (HNO2). This test capitalizes on the distinct reactivity of the two amines with nitrous acid, leading to observable differences in their behavior.

Understanding the Reaction

Aniline (C6H5NH2) is a primary aromatic amine, while benzylamine (C6H5CH2NH2) is a primary aliphatic amine. When each of these amines is treated with nitrous acid, they react differently due to the structural variations in their molecular frameworks.

The Test Procedure

  • Prepare a solution of nitrous acid by mixing sodium nitrite (NaNO2) with hydrochloric acid (HCl).
  • In a separate container, dissolve a small amount of the amine (either aniline or benzylamine) in water.
  • Slowly add the nitrous acid solution to the amine solution while keeping the mixture cool.

Observations

After adding nitrous acid:

  • Aniline: The reaction will produce a diazonium salt, which is typically stable at low temperatures. If the solution is warmed, the diazonium salt can decompose, leading to the formation of a colored azo compound, which can be identified by its characteristic color.
  • Benzylamine: In contrast, benzylamine will react with nitrous acid to form benzyl alcohol and nitrogen gas. This reaction does not produce a stable diazonium salt, and you may observe the evolution of gas bubbles, indicating the release of nitrogen.

Summary of Results

By observing the outcomes of the reaction with nitrous acid, you can effectively distinguish between aniline and benzylamine:

  • If you see the formation of a stable diazonium salt or a colored azo compound, you are dealing with aniline.
  • If gas bubbles are produced without the formation of a stable compound, then the amine is benzylamine.

This test is a straightforward and reliable method for differentiating these two amines based on their unique chemical properties. Understanding these reactions not only aids in identification but also provides insight into the behavior of different functional groups in organic chemistry.


question mark

is Pradeep Chemistry+Ncert sufficient for all of the theory of Jee Mains Chemistry?


Hi, I’m a self-study JEE 2027 aspirant with a large 11th backlog. Since I don’t think 6–8 hour one-shots are sufficient to cover the full theory + breadth of problem types of a JEE chapter, I’ve shifted from lecture-based preparation to book-based self-study.


I have a problem with using NCERT as my primary chemistry source. In my experience, it is concise and information-heavy, but often lacks detailed explanations, systematic organisation of concepts, and categorisation of problem types. This seems especially problematic for Physical and Organic Chemistry, where I feel that simply reading NCERT may not give enough depth or problem-solving preparation.


So I’m considering this approach:


Pradeep Chemistry → complete the chapter thoroughly from Pradeep → then read NCERT for that chapter → solve JEE Main PYQs/problems.


My main question is:


Is Pradeep + NCERT sufficient as the complete theory source for JEE Main-level Chemistry?


In other words, after thoroughly completing a chapter from Pradeep and then NCERT, can I consider the theory part of that chapter complete for JEE Main, with only PYQs/problem practice remaining?


I’m asking specifically about JEE Main level, not Advanced.


Also, if Pradeep is not sufficient, what specific gap does it leave, and what would you recommend as a better book-based alternative for self-study?

Grade 1212 grade chemistry others

Last Activity: 9 Days ago