Ethyl isocyanide on hydrolysis in acidic medium generates: (A) Propanoic acid and ammonium salt (B) Ethanoic acid and ammonium salt (C) Methylamine salt and ethanoic acid (D) Ethylamine salt and methanoic acid
To solve the question regarding the hydrolysis of ethyl isocyanide in acidic medium, let's first understand what ethyl isocyanide is and the process of hydrolysis.
Ethyl Isocyanide Structure
Ethyl isocyanide (or ethyl carbamate) has the following structure:
The isocyanide functional group is represented as –N≡C, where the nitrogen is triple-bonded to carbon, which is bonded to an ethyl group (C2H5).
Hydrolysis Reaction
When isocyanides undergo hydrolysis in an acidic medium, they typically react with water (H2O) in the presence of an acid (like HCl or H2SO4). The hydrolysis of isocyanides leads to the formation of carboxylic acids and amines.
Reaction Mechanism
The isocyanide reacts with water:
R-NC
+
H
2
O
→
R-COOH
+
NH
3
R-NC+H
2
O→R-COOH+NH
3
Here, R is the ethyl group (C2H5).
The hydrolysis process results in the formation of ethanoic acid (acetic acid, CH3COOH) and ammonia (NH3).
Products of Hydrolysis
The ethyl group (C2H5) transforms into ethanoic acid (CH3COOH).
The nitrogen from the isocyanide becomes ammonium (NH4+) in an acidic medium.
Conclusion
Thus, the hydrolysis of ethyl isocyanide in acidic medium produces ethanoic acid and ammonium salt.
Answer
The correct answer is: (B) Ethanoic acid and ammonium salt.
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