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12 grade chemistry others

Ethanol on reaction of acidified potassium dichromate form:

  • A. ethane
  • B. ethene
  • C. ethanal
  • D. ethanoic acid

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1 Year agoGrade
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

When ethanol reacts with acidified potassium dichromate, the primary product formed is ethanal, which is also known as acetaldehyde. This reaction is part of an oxidation process where ethanol, a primary alcohol, is oxidized to an aldehyde. Let's break down the reaction and the reasoning behind this outcome.

The Reaction Process

In the presence of acidified potassium dichromate, ethanol undergoes oxidation. The dichromate ion (Cr2O7^2-) acts as an oxidizing agent, facilitating the conversion of ethanol (C2H5OH) into ethanal (C2H4O). This transformation can be summarized in the following steps:

  • Oxidation of Ethanol: Ethanol is oxidized by losing hydrogen atoms. The hydroxyl group (-OH) is converted into a carbonyl group (C=O), resulting in the formation of ethanal.
  • Color Change: During this reaction, the orange color of the dichromate ion changes to green, indicating the reduction of chromium from +6 to +3 oxidation state.

Why Not the Other Options?

Let’s clarify why the other options—ethane, ethene, and ethanoic acid—are not the products of this reaction:

  • Ethane (A): This is an alkane and would not be formed through oxidation. Instead, it is a saturated hydrocarbon that does not contain functional groups that can be oxidized.
  • Ethene (B): Ethene is an alkene, which is formed through dehydration (loss of water) rather than oxidation. Ethanol can be dehydrated to form ethene under specific conditions, but that is not the case here with potassium dichromate.
  • Ethanoic Acid (D): While ethanal can further oxidize to form ethanoic acid (acetic acid), this reaction typically requires more vigorous conditions or a longer reaction time. In the context of the question, the immediate product of ethanol oxidation is ethanal.

Summary of the Reaction

In summary, when ethanol is treated with acidified potassium dichromate, the primary product formed is ethanal (C2H4O). This reaction exemplifies the oxidation of a primary alcohol to an aldehyde, showcasing the role of dichromate as a powerful oxidizing agent. Understanding these reactions is crucial in organic chemistry, as they form the basis for many synthetic pathways and transformations.


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is Pradeep Chemistry+Ncert sufficient for all of the theory of Jee Mains Chemistry?


Hi, I’m a self-study JEE 2027 aspirant with a large 11th backlog. Since I don’t think 6–8 hour one-shots are sufficient to cover the full theory + breadth of problem types of a JEE chapter, I’ve shifted from lecture-based preparation to book-based self-study.


I have a problem with using NCERT as my primary chemistry source. In my experience, it is concise and information-heavy, but often lacks detailed explanations, systematic organisation of concepts, and categorisation of problem types. This seems especially problematic for Physical and Organic Chemistry, where I feel that simply reading NCERT may not give enough depth or problem-solving preparation.


So I’m considering this approach:


Pradeep Chemistry → complete the chapter thoroughly from Pradeep → then read NCERT for that chapter → solve JEE Main PYQs/problems.


My main question is:


Is Pradeep + NCERT sufficient as the complete theory source for JEE Main-level Chemistry?


In other words, after thoroughly completing a chapter from Pradeep and then NCERT, can I consider the theory part of that chapter complete for JEE Main, with only PYQs/problem practice remaining?


I’m asking specifically about JEE Main level, not Advanced.


Also, if Pradeep is not sufficient, what specific gap does it leave, and what would you recommend as a better book-based alternative for self-study?

Grade 1212 grade chemistry others

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