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12 grade chemistry others

Discuss the nature of bonding in [Fe(CN)6]^{ - 4} on the basis of valence bond theory. What is the structure and magnetic characteristics? (At number Fe = 26).

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1 Year agoGrade
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To understand the bonding in the complex ion [Fe(CN)6]^{4-}, we need to delve into the principles of valence bond theory and how it applies to transition metal complexes. Iron (Fe), with an atomic number of 26, has the electron configuration of [Ar] 3d^6 4s^2. In the case of [Fe(CN)6]^{4-}, iron is in the +2 oxidation state, meaning it loses two electrons, typically from the 4s orbital and one from the 3d orbital, resulting in a 3d^6 configuration.

Bonding Characteristics

In [Fe(CN)6]^{4-}, the cyanide ion (CN^-) acts as a strong field ligand. According to valence bond theory, the interaction between the metal ion and the ligands involves the overlap of atomic orbitals. Here’s how it unfolds:

  • Hybridization: The central iron ion undergoes hybridization to form six equivalent orbitals. In this case, the 3d, 4s, and 4p orbitals combine to form six sp^3d^2 hybrid orbitals. This hybridization allows for optimal overlap with the lone pairs of electrons from the cyanide ligands.
  • Coordination Geometry: The arrangement of the six cyanide ligands around the iron ion leads to an octahedral geometry. This is typical for complexes with six ligands.
  • Bonding: Each CN^- ligand donates a pair of electrons to the iron, forming coordinate covalent bonds. The strong field nature of CN^- also promotes pairing of the electrons in the 3d orbitals, which is crucial for understanding the magnetic properties of the complex.

Magnetic Properties

The magnetic characteristics of [Fe(CN)6]^{4-} can be explained by examining the electron configuration after hybridization. In this complex, the presence of strong field ligands like cyanide leads to the pairing of electrons in the 3d orbitals. As a result, the electron configuration can be represented as:

  • 3d^6: All six electrons are paired.

This pairing results in no unpaired electrons, which is a key factor in determining the magnetic properties. Consequently, [Fe(CN)6]^{4-} is diamagnetic, meaning it is not attracted to a magnetic field.

Summary of Structure and Characteristics

In summary, the bonding in [Fe(CN)6]^{4-} involves:

  • Hybridization of the iron ion to form sp^3d^2 orbitals.
  • Octahedral geometry due to the arrangement of six cyanide ligands.
  • Diamagnetic properties resulting from the pairing of all electrons in the 3d orbitals.

This complex serves as a classic example of how ligand field theory and valence bond theory can be applied to understand the structure and properties of transition metal complexes. The strong field nature of cyanide not only influences the bonding but also plays a crucial role in determining the magnetic behavior of the complex.


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is Pradeep Chemistry+Ncert sufficient for all of the theory of Jee Mains Chemistry?


Hi, I’m a self-study JEE 2027 aspirant with a large 11th backlog. Since I don’t think 6–8 hour one-shots are sufficient to cover the full theory + breadth of problem types of a JEE chapter, I’ve shifted from lecture-based preparation to book-based self-study.


I have a problem with using NCERT as my primary chemistry source. In my experience, it is concise and information-heavy, but often lacks detailed explanations, systematic organisation of concepts, and categorisation of problem types. This seems especially problematic for Physical and Organic Chemistry, where I feel that simply reading NCERT may not give enough depth or problem-solving preparation.


So I’m considering this approach:


Pradeep Chemistry → complete the chapter thoroughly from Pradeep → then read NCERT for that chapter → solve JEE Main PYQs/problems.


My main question is:


Is Pradeep + NCERT sufficient as the complete theory source for JEE Main-level Chemistry?


In other words, after thoroughly completing a chapter from Pradeep and then NCERT, can I consider the theory part of that chapter complete for JEE Main, with only PYQs/problem practice remaining?


I’m asking specifically about JEE Main level, not Advanced.


Also, if Pradeep is not sufficient, what specific gap does it leave, and what would you recommend as a better book-based alternative for self-study?

Grade 1212 grade chemistry others

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