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11 grade physics others

Write three equations of uniformly accelerated motion relating the initial velocity (u), final velocity (v), acceleration (a), and displacement (S).
Derive the following equations for a uniformly accelerated motion:
A. v = u + at
B. s = ut + (1/2) a t²
C. v² = u² + 2as

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1 Year agoGrade
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1 Answer

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1 Year ago

To derive the equations of uniformly accelerated motion, we'll use the basic principles of kinematics. Here are the three key equations for uniformly accelerated motion, along with their derivations:

### 1. Equation: \( v = u + at \)

**Derivation:**

- Let \( u \) be the initial velocity.
- Let \( v \) be the final velocity.
- Let \( a \) be the acceleration.
- Let \( t \) be the time.

Acceleration is defined as the rate of change of velocity. Therefore, we can express acceleration as:

\[ a = \frac{v - u}{t} \]

Rearranging this equation to solve for \( v \):

\[ v = u + at \]

### 2. Equation: \( s = ut + \frac{1}{2}at^2 \)

**Derivation:**

- Let \( s \) be the displacement.

To derive this equation, we use the fact that displacement \( s \) is the area under the velocity-time graph, which forms a trapezoid in the case of constant acceleration.

1. **Average Velocity**: The average velocity \( \bar{v} \) for uniformly accelerated motion is given by:

\[ \bar{v} = \frac{u + v}{2} \]

2. **Displacement**: The displacement \( s \) is the average velocity multiplied by time:

\[ s = \bar{v} \cdot t \]

Substitute \( \bar{v} \) into the displacement formula:

\[ s = \frac{u + v}{2} \cdot t \]

Substitute \( v = u + at \) into the equation:

\[ s = \frac{u + (u + at)}{2} \cdot t \]

\[ s = \frac{2u + at}{2} \cdot t \]

\[ s = (u + \frac{1}{2}at) \cdot t \]

\[ s = ut + \frac{1}{2}at^2 \]

### 3. Equation: \( v^2 = u^2 + 2as \)

**Derivation:**

To derive this equation, we start with the two previously derived equations.

1. From \( v = u + at \), solve for \( t \):

\[ t = \frac{v - u}{a} \]

2. Substitute \( t \) into the displacement equation \( s = ut + \frac{1}{2}at^2 \):

\[ s = u \left(\frac{v - u}{a}\right) + \frac{1}{2} a \left(\frac{v - u}{a}\right)^2 \]

Simplify:

\[ s = \frac{u(v - u)}{a} + \frac{1}{2} \cdot \frac{a(v - u)^2}{a^2} \]

\[ s = \frac{u(v - u)}{a} + \frac{1}{2} \cdot \frac{(v - u)^2}{a} \]

\[ s = \frac{u(v - u) + \frac{1}{2} (v^2 - 2uv + u^2)}{a} \]

\[ s = \frac{v^2 - u^2}{2a} \]

Rearrange to solve for \( v^2 \):

\[ v^2 = u^2 + 2as \]

These three equations are fundamental in kinematics for analyzing uniformly accelerated motion.