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question mark

Initial phase of the particle executing SHM with y = 4sin(ωt) + 3cos(ωt) is:
A) 53°
B) 37°
C) 90°
D) 45°

Aniket Singh , 5 Months ago
Grade
anser 1 Answers
Askiitians Tutor Team

Last Activity: 5 Months ago

To find the initial phase of the particle executing Simple Harmonic Motion (SHM) described by the equation

=
4
sin

(


)
+
3
cos

(


)
y=4sin(ωt)+3cos(ωt), we need to express this equation in the standard form of

sin

(


+

)
Asin(ωt+ϕ), where

A is the amplitude and

ϕ is the phase angle.

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