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A uniform chain of length 2m is kept on a table such that a length of 60cm hangs freely from the edge of the table. The total mass of the chain is 4kg. What is the work done in pulling the entire chain on the table?A. 7.2 JB. 3.6 JC. 120 JD. 1200 J

Aniket Singh , 9 Months ago
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Askiitians Tutor Team

Last Activity: 9 Months ago

To find the work done in pulling the entire chain onto the table, we need to calculate the gravitational potential energy of the hanging portion and then convert it into work.

The mass of the hanging portion of the chain can be calculated using its length and the total mass of the chain. Since the hanging portion is 60 cm (or 0.6 m) long, we can set up the following proportion:

(0.6 m) / (2 m) = (mass of hanging portion) / (4 kg)

Cross-multiplying, we get:

(0.6 m) * (4 kg) = (2 m) * (mass of hanging portion)

2.4 kg = 2 m * (mass of hanging portion)

Dividing both sides by 2 m, we find:

mass of hanging portion = 2.4 kg / 2 m = 1.2 kg

The gravitational potential energy of the hanging portion is given by:

PE = m * g * h

Where:
m = mass of the hanging portion = 1.2 kg
g = acceleration due to gravity = 9.8 m/s^2
h = height of the hanging portion = 0.6 m

PE = (1.2 kg) * (9.8 m/s^2) * (0.6 m) = 7.056 J (rounded to three decimal places)

Therefore, the work done in pulling the entire chain onto the table is approximately 7.056 J.

Since none of the given answer choices match this result exactly, it seems there might be an error in the provided options. The closest option is A. 7.2 J, which is the most reasonable choice given the calculations.





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