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A small block of mass m kept at the left end of a larger block of mass M and length L. The system can slide on a horizontal road. The system is started towards right with an initial velocity v. The friction coefficient between the road and the bigger block is μ and that between the block is μ/2. Find the time elapsed before the smaller block separates from the bigger block.

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11 Months agoGrade
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ApprovedApproved Tutor Answer11 Months ago

To determine the time elapsed before the smaller block separates from the larger block, we need to analyze the forces acting on both blocks and their relative motion.

Understanding the Forces

When the system is set in motion, the larger block (mass M) experiences friction with the ground, while the smaller block (mass m) experiences friction with the larger block. The frictional forces can be expressed as:

  • Friction on the larger block: F_M = \mu M g
  • Friction on the smaller block: F_m = \frac{\mu}{2} m g

Acceleration Calculation

The frictional force on the larger block causes it to decelerate, while the smaller block also experiences a deceleration due to the friction with the larger block. The acceleration of the larger block can be calculated as:

a_M = -\frac{F_M}{M} = -\mu g

For the smaller block, the acceleration due to friction is:

a_m = -\frac{F_m}{m} = -\frac{\mu}{2} g

Relative Motion

The relative acceleration between the two blocks is:

a_{rel} = a_m - a_M = -\frac{\mu}{2} g + \mu g = \frac{\mu}{2} g

Time Until Separation

Initially, the smaller block is at rest relative to the larger block. The time until separation can be found using the equation of motion:

s = ut + \frac{1}{2} a_{rel} t^2

Here, s is the distance over which the smaller block will slide on the larger block before separation. This distance is equal to the length of the larger block, L, and the initial relative velocity is zero:

L = 0 + \frac{1}{2} \left(\frac{\mu}{2} g\right) t^2

Solving for t gives:

t^2 = \frac{2L}{\frac{\mu}{2} g} = \frac{4L}{\mu g}

Thus, the time elapsed before the smaller block separates from the larger block is:

t = \sqrt{\frac{4L}{\mu g}}