A ball is dropped downwards, after 1 sec another ball is dropped downwards from the same point. What is the distance between them after 3 sec? (Take g = 10 m/s^2)

To find the distance between the two balls after 3 seconds, we can use the equations of motion for free-falling objects. The equation for the distance traveled by an object in free fall is given by:

d = (1/2) * g * t^2

Where:
d = distance traveled (in meters)
g = acceleration due to gravity (given as 10 m/s^2)
t = time (in seconds)

For the first ball, which was dropped 1 second earlier, the time is 3 seconds, so we can calculate its distance traveled as follows:

d1 = (1/2) * 10 * (3)^2
d1 = 45 meters

For the second ball, which was dropped at the same point 1 second later, the time is 2 seconds, so we can calculate its distance traveled as follows:

d2 = (1/2) * 10 * (2)^2
d2 = 20 meters

Now, to find the distance between the two balls after 3 seconds, we subtract the distance traveled by the second ball from the distance traveled by the first ball:

Distance between the balls = d1 - d2
Distance between the balls = 45 meters - 20 meters
Distance between the balls = 25 meters

So, the distance between the two balls after 3 seconds is 25 meters.