Five persons A, B, C, D and E occupy the seats in a row such that A and B sit next to each other. In how many possible ways can these five people sit?

To find the number of possible ways these five people can sit in a row such that A and B sit next to each other, you can treat A and B as a single entity (let's call it AB). So, you have 4 entities to arrange: AB, C, D, and E.

Now, you can think of these 4 entities as if they are distinct and can be arranged in 4! (4 factorial) ways. However, within the AB entity, there are 2 ways to arrange A and B (AB or BA). So, you need to multiply the result by 2.

Therefore, the total number of possible ways these five people can sit with A and B sitting next to each other is:

4! * 2 = 24 * 2 = 48 ways.

So, there are 48 possible ways for A, B, C, D, and E to sit in a row with A and B sitting next to each other.