You have 25 mL of acetic acid (C{H_3}COOH) density =1.058 gm/L. How many grams do you have? How many mol do you have? How many molecules do you have? Help please

To find the number of grams, moles, and molecules of acetic acid, we'll follow these steps:

Step 1: Calculate the mass of the given volume of acetic acid.
Step 2: Convert the mass to moles using the molar mass of acetic acid.
Step 3: Calculate the number of molecules using Avogadro's number.

Step 1: Calculate the mass of the given volume of acetic acid.
Density = mass/volume
mass = density × volume

Given density = 1.058 g/mL
Volume = 25 mL

mass = 1.058 g/mL × 25 mL
mass = 26.45 grams

Step 2: Convert the mass to moles using the molar mass of acetic acid.
The molar mass of acetic acid (C₂H₄O₂) can be calculated as follows:

Molar mass (C) = 12.01 g/mol
Molar mass (H) = 1.01 g/mol
Molar mass (O) = 16.00 g/mol

Molar mass (C₂H₄O₂) = 2 × (Molar mass (C)) + 4 × (Molar mass (H)) + 2 × (Molar mass (O))
Molar mass (C₂H₄O₂) = 2 × 12.01 g/mol + 4 × 1.01 g/mol + 2 × 16.00 g/mol
Molar mass (C₂H₄O₂) = 24.02 g/mol + 4.04 g/mol + 32.00 g/mol
Molar mass (C₂H₄O₂) = 60.06 g/mol

Now, we can calculate the number of moles:

moles = mass / molar mass
moles = 26.45 g / 60.06 g/mol
moles ≈ 0.4405 moles

Step 3: Calculate the number of molecules using Avogadro's number.
Avogadro's number (Nₐ) is approximately 6.022 × 10²³ molecules/mol.

Number of molecules = moles × Avogadro's number
Number of molecules = 0.4405 moles × 6.022 × 10²³ molecules/mol
Number of molecules ≈ 2.652 × 10²³ molecules

So, in the given 25 mL of acetic acid, you have approximately:

26.45 grams of acetic acid
0.4405 moles of acetic acid
2.652 × 10²³ molecules of acetic acid.