When phenol is treated with excess bromine water, it undergoes bromination reactions. Phenol contains a benzene ring with a hydroxyl (OH) group attached to it, making it susceptible to electrophilic aromatic substitution reactions.
In the presence of excess bromine water, bromine (Br2) adds to the phenol ring. Initially, one bromine atom substitutes the hydrogen atom on the benzene ring to form 2-bromophenol. If the reaction continues with excess bromine, additional bromine atoms can substitute other hydrogen atoms on the ring.
So, as the reaction progresses with excess bromine, it can lead to the formation of a mixture of brominated phenol products, including o-bromophenol (2-bromophenol), m-bromophenol (3-bromophenol), and p-bromophenol (4-bromophenol). Therefore, the correct answer is:
B. o- and p-bromophenol