When acetone and chloroform are mixed, hydrogen bonding takes place between them. Such a liquid pair will cause:A.Positive deviation from Raoult’s lawB.Negative deviation from Raoult’s lawC.No deviation from Raoult’s lawD.Cannot be predicted

Acetone and chloroform do not form hydrogen bonds with each other. In fact, both acetone and chloroform are relatively non-polar substances. Hydrogen bonding typically occurs between molecules with hydrogen attached to highly electronegative atoms (such as oxygen, nitrogen, or fluorine).

When two liquids are mixed, the resulting mixture can exhibit either positive or negative deviations from Raoult's law, depending on the interactions between the molecules.

If the interactions between the molecules in the mixture are weaker than those predicted by Raoult's law, it leads to positive deviation.
If the interactions are stronger than predicted, it leads to negative deviation.
Since acetone and chloroform do not form hydrogen bonds with each other, the interactions are not particularly strong or weak. Therefore, the mixture of acetone and chloroform is expected to show little to no deviation from Raoult's law.

So, the correct answer is:
C. No deviation from Raoult’s law