What is the oxidation state of K in KO2?

Options-

(A) - 1

(B) - 2

(C) + 1

(D) 0

To determine the oxidation state of potassium (K) in potassium superoxide (KO2), we need to analyze the compound's structure and the typical oxidation states of its components. In KO2, potassium is combined with the superoxide ion (O2^-), which has a unique oxidation state.

Breaking Down the Components

First, let's look at the superoxide ion. The superoxide ion consists of two oxygen atoms and carries a -1 charge overall. In this ion, one of the oxygen atoms has an oxidation state of -1, while the other has an oxidation state of 0. This is because superoxide is a radical species, and the distribution of oxidation states can be a bit unconventional.

Assigning Oxidation States

Now, we can set up an equation based on the overall charge of the compound. The compound KO2 is neutral, meaning the sum of the oxidation states must equal zero. Let’s denote the oxidation state of potassium as x.

• Oxidation state of K = x
• Oxidation state of O2^- = -1

Since there is one potassium atom and one superoxide ion in the formula, we can write the equation:

x + (-1) = 0

Solving for x gives us:

x = +1

Conclusion on Oxidation State

Thus, the oxidation state of potassium (K) in KO2 is +1. This aligns with the typical behavior of alkali metals, which usually have an oxidation state of +1 in their compounds. Therefore, the correct answer is (C) +1.