What is the concentration of sugar (C₁₂H₂₂O₁₁) in mol L^-1 if it’s 20 g are dissolved in enough water to make a final volume up to 2 L?

To find the concentration of sugar (C₁₂H₂₂O₁₁) in mol/L, we first need to calculate the number of moles of sugar in 20 grams.

Step 1: Calculate Molar Mass

The molar mass of sugar (C₁₂H₂₂O₁₁) can be calculated as follows:

• Carbon (C): 12.01 g/mol × 12 = 144.12 g/mol
• Hydrogen (H): 1.008 g/mol × 22 = 22.176 g/mol
• Oxygen (O): 16.00 g/mol × 11 = 176.00 g/mol

Total Molar Mass: 144.12 + 22.176 + 176.00 = 342.296 g/mol

Step 2: Calculate Moles of Sugar

Now, we can find the number of moles of sugar in 20 grams:

Moles of sugar: Moles = mass (g) / molar mass (g/mol)

Moles = 20 g / 342.296 g/mol ≈ 0.0584 moles

Step 3: Calculate Concentration

Finally, we can calculate the concentration in mol/L:

Concentration (C): C = moles / volume (L)

C = 0.0584 moles / 2 L = 0.0292 mol/L

Final Answer

The concentration of sugar in the solution is approximately 0.0292 mol/L.