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11 grade chemistry others

What is relative lowering of vapor pressure? How is it useful in determining the molar mass of a solute?

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11 Months agoGrade
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ApprovedApproved Tutor Answer11 Months ago

Relative lowering of vapor pressure refers to the decrease in the vapor pressure of a solvent when a non-volatile solute is added. This phenomenon occurs because the presence of solute particles reduces the number of solvent molecules that can escape into the vapor phase.

Understanding Vapor Pressure

Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid phase. When a solute is dissolved in a solvent, the vapor pressure of the solvent decreases compared to its pure state.

How It Works

  • The formula for relative lowering of vapor pressure is: ΔP/P₀ = n₁/(n₁ + n₂)
  • Here, ΔP is the change in vapor pressure, P₀ is the original vapor pressure of the pure solvent, n₁ is the number of moles of solute, and n₂ is the number of moles of solvent.

Application in Molar Mass Determination

This concept is particularly useful in calculating the molar mass of a solute. By measuring the decrease in vapor pressure, one can determine the concentration of the solute in the solution.

Steps to Calculate Molar Mass

  • Measure the vapor pressure of the pure solvent.
  • Add a known amount of solute and measure the new vapor pressure.
  • Calculate the relative lowering of vapor pressure.
  • Use the formula to find the molar mass of the solute based on the known quantities.

In summary, the relative lowering of vapor pressure is a key concept in colligative properties, allowing scientists to determine the molar mass of solutes effectively through experimental measurements.