What happens when Copper sulphate reacts with potassium iodide?

When copper sulfate (CuSO₄) reacts with potassium iodide (KI), a redox reaction occurs. The reaction can be described as follows:

Oxidation-Reduction Reaction: Copper(II) ions (Cu²⁺) in the copper sulfate are reduced to copper(I) ions (Cu⁺), while iodide ions (I⁻) are oxidized to iodine (I₂). The overall balanced chemical reaction is: Observations:

Color Change: The solution will typically change color. Copper(II) sulfate is blue, while iodine is brownish-yellow. As the reaction progresses, the blue color of the copper sulfate solution will turn brown due to the formation of iodine.
Precipitate Formation: Copper(I) iodide (CuI) is a white precipitate that may form in the reaction mixture.
This reaction is often used to demonstrate the concept of oxidation and reduction in chemistry.