Using the data given below find out the strongest reducing agent.

• E°_Cr₂O₄/Cr³⁺ = 1.33V
• E°_MnO₄⁻/Mn²⁺ = 1.51V
• E°_Cl₂/Cl⁻ = 1.36V
• E°_Cr³⁺/Cr = -0.74V

A. Cl⁻

B. Mn²⁺

C. Cr

D. Cr³⁺

To determine the strongest reducing agent from the given data, we need to look at the standard reduction potentials (E°) provided. The more negative the E° value, the stronger the reducing agent. Here are the relevant potentials:

• E° Cr₂O₄ /Cr³⁺ = 1.33 V
• E° MnO₄ ⁻/Mn²⁺ = 1.51 V
• E° Cl₂ /Cl⁻ = 1.36 V
• E° Cr³⁺ /Cr = -0.74 V

Now, let's analyze the options:

• Cl⁻: This is the reduced form of Cl₂, which has a positive E° value (1.36 V), indicating it is not a strong reducing agent.
• Mn²⁺: This is the reduced form of MnO₄⁻, with a positive E° value (1.51 V), also indicating it is not a strong reducing agent.
• Cr: This is the reduced form of Cr³⁺, with a very negative E° value (-0.74 V), suggesting it is a strong reducing agent.
• Cr³⁺: This is the oxidized form of Cr, and it has a positive E° value (1.33 V), indicating it is not a reducing agent.

Based on this analysis, the strongest reducing agent among the options is Cr, as it has the most negative standard reduction potential.