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11 grade chemistry others

To derive an expression for the integrated rate law for a zero order reaction, we start with the general rate equation:

Rate = -d[A]/dt = k

For a zero order reaction, the rate is constant and does not depend on the concentration of the reactant. Thus, we can express this as:

-d[A] = k dt

Integrating both sides, we get:

∫d[A] = -k ∫dt

This results in:

[A] - [A]0 = -kt

Rearranging gives us the integrated rate law for a zero order reaction:

[A] = [A]0 - kt

Where [A]0 is the initial concentration of the reactant, k is the rate constant, and t is time.

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11 Months agoGrade
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ApprovedApproved Tutor Answer11 Months ago

To derive the integrated rate law for a zero-order reaction, we start with the fundamental rate equation:

Understanding the Rate Equation

The rate of a zero-order reaction is expressed as:

Rate = -d[A]/dt = k

Here, k is the rate constant, and importantly, the rate remains constant regardless of the concentration of the reactant.

Setting Up the Equation

We can rewrite the equation as:

-d[A] = k dt

Integrating Both Sides

Next, we integrate both sides:

∫d[A] = -k ∫dt

This integration leads to:

[A] - [A]₀ = -kt

Final Expression

By rearranging the equation, we arrive at the integrated rate law for a zero-order reaction:

[A] = [A]₀ - kt

Key Variables

  • [A]₀: Initial concentration of the reactant
  • k: Rate constant
  • t: Time

This expression shows how the concentration of the reactant decreases linearly over time in a zero-order reaction.