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11 grade chemistry others

Three sparingly soluble salts have same solubility products are given below:

  • I. A₂X
  • II. AX
  • III. Aₓ₃

Their solubility in a standard solution will be such that:

  • A: III > II > I
  • B: III > I > II
  • C: II > III > I
  • D: II > I > III

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11 Months agoGrade
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1 Answer

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ApprovedApproved Tutor Answer11 Months ago

To determine the solubility of the three salts A₂X, AX, and Aₓ₃, we need to analyze their dissociation in water and how their solubility products (Ksp) relate to their solubility.

Understanding the Salts

Each salt dissociates into ions in solution:

  • A₂X: Dissociates into 2A+ and X2-
  • AX: Dissociates into A+ and X2-
  • Aₓ₃: Dissociates into A3+ and 3X2-

Calculating Solubility

The solubility product (Ksp) is related to the concentration of the ions in solution:

  • For A₂X: Ksp = [A+]2 * [X2-]
  • For AX: Ksp = [A+] * [X2-]
  • For Aₓ₃: Ksp = [A3+] * [X2-]3

Comparing Solubility

Since all salts have the same Ksp, we can compare their solubility:

  • A₂X produces more A+ ions, leading to lower solubility.
  • AX has a moderate solubility.
  • Aₓ₃ produces fewer A+ ions due to its higher charge, resulting in higher solubility.

Final Ranking

Based on this analysis, the order of solubility from highest to lowest is:

Aₓ₃ > AX > A₂X

Thus, the correct answer is:

A: III > II > I