The correct answer is D. Diborane (B2H6) contains four 2C-2e bonds and four 3C-2e bonds.
Diborane is a chemical compound with the formula B2H6. It consists of two boron atoms (B) and six hydrogen atoms (H). Each boron atom forms four sigma (σ) bonds, known as 2-center-2-electron (2C-2e) bonds, with the four hydrogen atoms directly attached to it. These sigma bonds are formed by the overlap of the boron's sp3 hybrid orbitals with the hydrogen's 1s orbitals.
In addition to the 2C-2e bonds, diborane also contains four 3-center-2-electron (3C-2e) bonds. These are known as banana bonds or bridging bonds. Each boron atom forms a 3C-2e bond with two hydrogen atoms and shares the electrons in the bond with a hydrogen atom from the adjacent boron atom. These bonds result from the overlap of the boron's empty p orbital with the hydrogen's 1s orbital.
Therefore, the structure of diborane (B2H6) contains four 2C-2e bonds and four 3C-2e bonds.