The oxidation number of Mn in the product of alkaline oxidative fusion of MnO2 is:

The oxidation number of manganese (Mn) in the product of alkaline oxidative fusion of MnO2 can be determined by analyzing the chemical reaction involved. In this process, MnO2 typically reacts with an alkaline medium, leading to the formation of manganese compounds such as potassium permanganate (KMnO4).

Oxidation State Calculation

In potassium permanganate (KMnO4), the oxidation state of potassium (K) is +1, and each oxygen (O) has an oxidation state of -2. The overall charge of the compound is neutral (0).

Setting Up the Equation

To find the oxidation state of Mn in KMnO4, we can set up the following equation:

• Let the oxidation state of Mn be x.
• The equation becomes: x + 1 + 4(-2) = 0.

Solving for x

Now, simplifying the equation:

• x + 1 - 8 = 0
• x - 7 = 0
• x = +7.

Final Result

Thus, the oxidation number of manganese in the product of alkaline oxidative fusion of MnO2 is +7.