The number of ions formed when cuprammonium sulphate is dissolved in water is.A) ZeroB) 1C) 2D) 4

Cuprammonium sulfate is a complex salt formed from copper sulfate and ammonia. When it dissolves in water, it dissociates into ions. To determine the number of ions formed, let's break it down:

1. **Chemical Formula**: The chemical formula of cuprammonium sulfate is \([Cu(NH_3)_4]SO_4\). This indicates it consists of a complex ion \([Cu(NH_3)_4]^{2+}\) and a sulfate ion \((SO_4)^{2-}\).

2. **Dissociation in Water**:
- \([Cu(NH_3)_4]SO_4\) dissociates into:
- \([Cu(NH_3)_4]^{2+}\) (the cuprammonium ion)
- \(SO_4^{2-}\) (the sulfate ion)

3. **Counting the Ions**:
- The \([Cu(NH_3)_4]^{2+}\) ion counts as 1 ion.
- The \(SO_4^{2-}\) ion counts as 1 ion.

Thus, when cuprammonium sulfate dissolves, it forms a total of 2 ions in solution.

**Answer: C) 2**