The hybridization and geometry of BrF3 molecules areA. s{{p}^{3}}d and T shaped.B. s{{p}^{2}}{{d}^{2}} and tetragonalC. s{{p}^{3}}dand bentD. None of the above
The hybridization and geometry of BrF3 molecules are:
C. sp3d and bent.
In BrF3, bromine (Br) forms three sigma (σ) bonds with three fluorine (F) atoms, and there is one lone pair of electrons on bromine. To accommodate the bonding and lone pair electrons, the central bromine atom undergoes sp3d hybridization, forming five hybrid orbitals. These five hybrid orbitals are used to create three sigma bonds with the fluorine atoms and one sigma bond with a lone pair of electrons, resulting in a bent molecular geometry. So, the correct answer is option C.
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