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11 grade chemistry others

The H-F and the H-I bond have different values for their bond polarity. Which of the following statements correctly identifies the bond that is more polar and gives the correct reason for this difference?(A) The H-F bond is more polar than the H-I bond because iodine is more electronegative than fluorine.(B) The H-F bond is more polar than the H-I bond because fluorine is more electronegative than iodine.(C) The H-I bond is more polar than the H-F bond because iodine is more electronegative than fluorine.(D) The H-I bond is more polar than the H-F bond because fluorine is more electronegative than iodine.

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1 Year agoGrade
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1 Year ago

(B) The H-F bond is more polar than the H-I bond because fluorine is more electronegative than iodine.

Electronegativity is the tendency of an atom to attract shared electrons in a covalent bond. Fluorine is the most electronegative element on the periodic table, while iodine is less electronegative. Therefore, in the H-F bond, fluorine attracts the shared electrons more strongly than iodine does in the H-I bond, resulting in a greater difference in electronegativity and a more polar bond.