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question mark

The entropy change can be calculated by using the expression ΔS=qrevT
. when water freezes in a glass beaker, choose the correct statement amongst the following.
A.ΔS
(system) decreases but ΔS
(surroundings) remains the same
B.ΔS
(system) increases but ΔS
(surroundings) decreases
C.ΔS
(system) decreases but ΔS
(surroundings) increases
D.ΔS
(system) decreases but ΔS
(surroundings) also decreases

Aniket Singh , 9 Months ago
Grade
anser 1 Answers
Askiitians Tutor Team

Last Activity: 9 Months ago

To determine the correct statement about the entropy change when water freezes in a glass beaker, we need to consider the entropy changes in both the system (water) and the surroundings.

Entropy change of the system (water):

When water freezes, it transitions from a liquid state to a solid state.
The solid state is more ordered than the liquid state, meaning the entropy of the water (system) decreases.
Entropy change of the surroundings:

Freezing is an exothermic process, meaning it releases heat to the surroundings.
The release of heat increases the entropy of the surroundings because heat dispersal increases disorder.

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